as of 11.14
I have no idea how the tie breakers work, but your logic sounds correct.I dont See why we would need va tech to lose twice?
if va tech, Miami, uva, Pitt all end up 5 and 3 Miami would have the tie breaker right?
I think i read that the next tie breaker is record vs tied teams. VT would have the same record as Miami (2-1) in such scenario.I have no idea how the tie breakers work, but your logic sounds correct.
Except we lost to V-tech.I have no idea how the tie breakers work, but your logic sounds correct.
Miami is 4-3 with 1 ACC game left with a best possible scenario of 5-3I dont See why we would need va tech to lose twice?
if va tech, Miami, uva, Pitt all end up 5 and 3 Miami would have the tie breaker right?
I think uva will win itThe most simple way to figure it is VT won't lose to GT & will be representing the CoaRstal.
We don't NEED Vtech to lose to both GTech and Pitt, we just need them to lose to Pitt. It would definitely help us, but it wouldn't absolutely be neccessary. We would have the tie breaker in the event of a 4 way tie between US, UVA, VTech, and Pitt if that's what it came down to. Because UVA will have lost to us and Vtech, Vtech will have lost to Pitt and UVA, and Pitt will have lost to UVA and us. The only team in that group of 4 with 2 wins vs the other teams is us, giving us the tie breaker.Miami is 4-3 with 1 ACC game left with a best possible scenario of 5-3
Virginia tech is currently 3-2 with 3 games left. Best possible scenario 6-2 which eliminates miami
Virginia leads and has one more game left against virginia tech
We need tech to end up at 4-4 (eliminating themselves) while also beating virginia so we can own the tiebreaker over virginia.
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We only need 4 games for us to win the Coastal. Not 5, so it'd be double those chances (assuming 50/50).As I’ve said in another thread, using some simple statistical modeling, our chances are 3% (0.03125). Tonight‘s result changed nothing.
The only mathematical quibble you might have with my calculation is that I assume each desired result as having a 50-50 chance of occurring. In other words a coin toss. Which considering that the remaining matches are somewhat evenly matched, that’s not a terrible assumption.
Changing some of the contests to 70/30 or 60/40, really doesn’t change the end result that much. It’s still going to be a single digit percentage probability.
In other words while the probably probability isn’t zero, it’s **** close to it
We only need 4 games for us to win the Coastal. Not 5, so it'd be double those chances (assuming 50/50).
If we assume our game against Duke is a 100% chance of winning (because if we don't this is all pointless anyways), then the chances are 12.5%.