2026 ACC Tiebreaker Unveiled at Media Days

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How do you have some of your league playing 9 games and some playing 8.. Just cant take any of this serious..

Rampage Jackson What GIF by United Fight League
 
And, shockingly, I have absolutely no idea how it works. The most ACC thing ever.

I understand it's not easy to do with most of your league playing 9 games, but some of your league playing 8 games, but does this make sense to anyone?

Perhaps the 1200 attorneys we have here can break this down for us.

We're almost there.. thank God for the big two or really the big one (PAUSE)
 
So what I’m gathering is if you only play 8, you are at a disadvantage? Sweet conference
 
The team with 9 games will always have a better winning percentage than one with 8 games if they won the same amount of games. But I didn’t read it very hard. Maybe there’s a way they balance that
 
Here's the part I don't understand:

2. Once the tied teams have been identified:
A) In the event of a tie involving teams which played an alternate number of conference games, all ties will be broken starting with the highest win percentage, working downward

Doesn't that imply an 8-0 team will break the tie against an 8-1 team? Or win percentage against the other tied teams?

It seems they're basically saying if there's no head to head tiebreaker it goes to a sportssource analytics ranking.
 
Here's the part I don't understand:

2. Once the tied teams have been identified:
A) In the event of a tie involving teams which played an alternate number of conference games, all ties will be broken starting with the highest win percentage, working downward

Doesn't that imply an 8-0 team will break the tie against an 8-1 team? Or win percentage against the other tied teams?

It seems they're basically saying if there's no head to head tiebreaker it goes to a sportssource analytics ranking.
What im saying. Better win all your games if you have 8 total games or look out for Tom foolery
 
And, shockingly, I have absolutely no idea how it works. The most ACC thing ever.

I understand it's not easy to do with most of your league playing 9 games, but some of your league playing 8 games, but does this make sense to anyone?

Perhaps the 1200 attorneys we have here can break this down for us.


Just about everything about the ACC is illogical, short-sighted, or outright dumb, so there really isn't a "short" way to break this down. Here is my best understanding/explanation of the nonsense they've set up by stupidly having an odd number of teams and an odd number of conference games for (most) teams:

1. Find the best team(s) by conference win percentage. But, also:

2. Any team that plays less than 9 games with either the same number of Ls or Ws, is considered a "tied team" (so there's less of a disadvantage for playing fewer games). Example: Team A goes 8-0 in conference play, Team is 8-1, Team C is 7-1, and Team D is 7-2. Team A goes to the ACCCG, Team B and C are considered "tied teams" and the 2-way tie rules below apply, and Team D is out.

Once you've figured out who the "tied teams" are:

3. If you have a 2-way tie, apply the 2-way tie rules: 1) Head to Head; 2) "Team Success Ranking"; and 3) a draw by the Commissioner (name out of a hat).

4. If you have a 3-way tie, apply the 3-way tie rules, which go down two different paths for common opponents versus non-common opponents:
5. If all 3 "tied teams" are common opponents: 1) best record (which includes the definition of No. 2 above, again to minimize disadvantage of playing only 8); 2).

6. If all 3 "tied teams" are not common opponents: 1) any team that went 2-0 against the other tied teams goes to the ACCCG, and any team that went 0-2 gets removed; 2) "Team Success Ranking"; and 3) a draw by the Commissioner. Only caveat here is once one team is drawn, the tie-breaker may need to be restarted from the top between the two remaining teams (if, for example, you have a 3-way tie for both ACCCG sports).
 
Here's the part I don't understand:

2. Once the tied teams have been identified:
A) In the event of a tie involving teams which played an alternate number of conference games, all ties will be broken starting with the highest win percentage, working downward

Doesn't that imply an 8-0 team will break the tie against an 8-1 team? Or win percentage against the other tied teams?

It seems they're basically saying if there's no head to head tiebreaker it goes to a sportssource analytics ranking.

No. In your example, those are not "tied teams". The 8-0 team has a higher win percentage (100%) than the 8-1 team (88.9%).

What im saying. Better win all your games if you have 8 total games or look out for Tom foolery

No. See my example above.
 
No. In your example, those are not "tied teams". The 8-0 team has a higher win percentage (100%) than the 8-1 team (88.9%).



No. See my example above.
So 8-0 automatically ahead of 8-1? I’m genuinely asking. In a meeting can’t read it in depth. That doesn’t seem like a great system since who is to say the 8-0 team wouldn’t be 8-1 if they played 9 games. Again I’m reading sparingly. May be missing a key point of your post/the ACC post
 
No. In your example, those are not "tied teams". The 8-0 team has a higher win percentage (100%) than the 8-1 team (88.9%).



No. See my example above.

In the section above that it says teams with dissimilar number of games tie based on identical number of wins or losses. So an 8-0 team ties an 8-1 team and a 8-1 team ties a 7-1 team. The next section is the one I quoted.
 
In the section above that it says teams with dissimilar number of games tie based on identical number of wins or losses. So an 8-0 team ties an 8-1 team and a 8-1 team ties a 7-1 team. The next section is the one I quoted.
Ahh this is what I missed then. Thanks
 
In the section above that it says teams with dissimilar number of games tie based on identical number of wins or losses. So an 8-0 team ties an 8-1 team and a 8-1 team ties a 7-1 team. The next section is the one I quoted.
So is this then a 3 way tie and they pick the top 2 from these 3? What a cluster ****
 
The team with 9 games will always have a better winning percentage than one with 8 games if they won the same amount of games. But I didn’t read it very hard. Maybe there’s a way they balance that
Incorrect, the opposite is true.
 
In the section above that it says teams with dissimilar number of games tie based on identical number of wins or losses. So an 8-0 team ties an 8-1 team and a 8-1 team ties a 7-1 team. The next section is the one I quoted.

Again, no to the bolded. An 8-0 team does NOT tie an 8-1 team. The 8-0 team has the better winning percentage, so they are not "tied teams" pursuant to Section 1. The section you are quoting from starts with "once the tied teams have been determined," making it inapplicable in your example. And if you are thinking Section 1.b. can be applied to have an 8-1 team "tie" an 8-0 team, you are misreading that section, which can only ever apply for the benefit of the team playing the alternate schedule (i.e., 8 games).

The part in italics is correct, though, but you're expressing it opposite of how I would. The 8-1 team has the better winning percentage than the 7-1 team. But, under Section 1.b., the 7-1 team is considered tied with the 8-1 team.
 
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